#1
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͹ءÃÁ
͹ءÃÁ???·Ó䧤ÃѺ
ãËé $A = \frac{1}{1^2} + \frac{1}{3^2} + \frac{1}{5^2} + ...$ áÅÐ $B = \frac{1}{2^2} + \frac{1}{4^2} + \frac{1}{6^2} + ... $ ¨§ËÒÇèÒ $\frac{A}{B} = ?$ 20 ÊÔ§ËÒ¤Á 2014 19:09 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 2 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ gon |
#2
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$B = \frac{1}{2^2}(\frac{1}{1^2} + \frac{1}{2^2} + \frac{1}{3^2} + ...)$
´Ñ§¹Ñé¹ $B = \frac{1}{4}(A+B)$
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#3
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áÅéÇ䧵èÍ
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#4
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á¡éÊÁ¡ÒÃà»ç¹ËÃ×Íà»ÅèÒ¤ÃѺ.
àªè¹ ¶éÒÁÕ $3A = 2B$ áÅéǨÐä´éÇèÒ $\frac{A}{B} = ?$
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#5
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B=(1/4)A+(1/4)B
=(3/4)B=(1/4)A =B=(1/3)A ;3B=A
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