#1
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µÃÕ⡳ÁÔµÔ
1. A = (sin 100 - sin 40)/(cos130 + cos 10) áÅÐ B = 4kcos70cos50 ÁÕA=B áÅéÇ ksin10 = ?
2.¶éÒ sin(13A/5) = X áÅéÇ cos (26A/5)*tan(13A/10) =? |
#2
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ÍéÒ§ÍÔ§:
$A = 1$ µÃ§ä»µÃ§ÁÒ ¨Ò¡¹Ñé¹ãªé $\cos(60^{\circ} - x) \cos(60^{\circ} + x) \cos(x) = \frac{\cos 3x}{4}$ â´Âá·¹ $x = 10^{\circ}$ ´Ñ§¹Ñé¹ $k\sin{10^{\circ}} = \frac{\sin 20^{\circ}}{\sqrt{3}}$ |
#3
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ÍéÒ§ÍÔ§:
᧧§§§ ˹Ùä´é A=tan70 ÍÐ |
#4
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