#1
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็Help
$tan A - sec A = \sqrt[3]{37}$
จงหา${(tan A + sec A)}^3$ |
#2
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$sec^2A-tan^2A=1------(1)$
$tanA-secA=\sqrt[3]{37}\rightarrow secA-tanA=-\sqrt[3]{37}-----(2)$ $(1)/(2); secA+tanA=-\frac{1}{\sqrt[3]{37}}$ $(secA+tanA)^3=-\frac{1}{37}$ |
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